In article <tak5n2tbr9iuq5pcupjdrgl6umjdustjtt.TakeThisOut@4ax.com>, Raphael Bustin
<rafeb.TakeThisOut@speakeasy.net> writes
>On 3 Dec 2006 05:18:42 -0800, "Conrad" <cweiler1.TakeThisOut@mac.com> wrote:
>
>>Hi,
>>
>>I'm guessing that a 1/2.5" sensor is larger than a 1/2.3" sensor. Is
>>this correct?
>
>No, that's exactly wrong. It is indeed a fraction, so
>the larger the denominator, the smaller the sensor.
>The fraction refers to the diagonal of sensor in inches.
>
>So 1/2.5" = 0.4" diagonal. 1/1.8" = 0.56" diagonal.
>
Except that the inches are about 17mm rather than 25.4mm due a
historical nomenclature quirk, whereby a 1" diameter vidicon tube had a
useful image diagonal of 16-18mm depending on how critical the camera
designer was. An extra few picture lines of resolution in the centre at
the expense of increased edge and corner distortion, that sort of thing.
So 1/2.5" = 17mm /2.5 = 6.8mm diagonal (only 0.27", not 0.4")
and 1/1.8" = 17mm / 1.8 = 9.4mm diagonal (only 0.37", not 0.56").
It is quite surprising that such nomenclature is still in use since
marketing types can only comprehend "bigger is better", but I guess they
are well used to telling their WAGs that 150mm is actually 9".
--
Kennedy
Yes, Socrates himself is particularly missed;
A lovely little thinker, but a bugger when he's pissed.
Python Philosophers (replace 'nospam' with 'kennedym' when replying)
>> Stay informed about: Sensors